Решение задач и контрольных на заказ

Домашняя

________________

Домашняя
Англ. яз.
Высшая математика
Физика
Теория вероятностей
Статистика
Мат. программирование
Дискретная математика
Программирование
Электротехника
ТерМех
Биология
Химия
Экономика
Курсовые
Все предметы
УО
Вакансии

 

Решение задач и контрольных работ по Физике выполняется как "вручную" (т.е. решение в рукописном виде), так и в компьютерном виде (формат Word, Pdf). Срок решения задач или контрольных по физике составляет 2-3 дня. В решении задач по физике присутствует краткое описание хода решения, а также все необходимые формулы и проверка размерности. Помимо общей физики мы решаем смежные предметы:

  • Биофизика
  • Сопротивление материалов (сопромат)
  • Строительная механика (строймех)
  • Теоретическая механика (теормех)
  • Техническая механика
  • Механика
  • Теплотехника
  • Гидравлика

 

Контакты

Для заказа решения задач по Физике
E-mail zakaz@physmath-help.ru
ICQ     5-74-35-55-70
Skype Alexandrp1

Заказать работу

   

Заказать решение задач по Физике, вы можете воспользовавшись формой заказа

 Заказать работу

или выслать письмо на указанный выше e-mail.

Решение задач и контрольных работ по физике выполняются практически по всем разделам физики:

  • Механика (Пример решения)
  • Молекулярная физика
  • Электричество и магнетизм (Пример решения)
  • Колебания и волны
  • Оптика
  • Элементы квантовой физики атомов и молекул
  • Элементы физики атомного ядра и элементарных частиц

Рекомендуемая литература по физике:

  • Фирганг Е. В. Руководство к решению задач по курсу общей физики. Учеб. Пособие для втузов. М., «Высш. школа», 1977
  • Трофимова Т. И. Курс физики. Задачи и решения. Учеб пособие для втузов. 2004 г.
  • Гладской В. М., Самойленко П. И. Сборник задач по физике с решениями: пособие для втузов, М. Дрофа, 2007 г.
 

Имеющиеся сборники задач по физике для заказа контрольных работ:

  • Физика. Методические указания и контрольные задания. Под ред. А. Г. Чертова. Москва1987
Работы по Физике, Термодинамике, Гидравлике выполнялись для Вузов:
Работы выполнялись для Вузов:
  • Дальневосточный государственные технический университет
  • Дальневосточный гос. ун-т путей сообщения (ДВГУПС)
  • Ивановская государственная текстильная академия
  • МГАУ им В.П. Горячкина
  • Московская финансово-юридическая академия
  • Московский гос. ун-т технологий и управления (МГУТУ)
  • Московский государственный открытый университет (МГОУ)
  • Московский государственный технический университет (МАМИ)
  • Мурманский государственный технический университет
  • Нижегродская медицинская академия
  • РГОТУПС/ РОАТ/ МИИТ
  • РГТЭУ
  • Российский государственный аграрный заочный университет (РГАЗУ)
  • Санкт-Петербургский государственный технологический университет растительных полимеров (СПбГТУРП)
  • Смоленская государственная медицинская академия (СГМА)
  • Тихоокеанский Государственный Университет (ТОГУ)
  • ТулГУ
  • Челябинская мед.академия

 

 


 

Возврат в начало

Пример решения задачи по физике1.

Движение точки описывается уравнением S= 2 t 3 10 t 2 +8 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmaiaadshadaahaaWcbeqaaiaaiodaaaGccqGHsislcaaIXaGaaGimaiaadshadaahaaWcbeqaaiaaikdaaaGccqGHRaWkcaaI4aaaaa@3E90@

. Найти скорость и ускорение точки в момент t=4с.

Дано: S=2 t 3 10 t 2 +8 t=4с ________________ V? a? | MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaqGaaqaabeqaaiaadsbbcaWGWqGaamypeiaad6dbcaGG6aaabaGaam4uaiabg2da9iaaikdacaWG0bWaaWbaaSqabeaacaaIZaaaaOGaeyOeI0IaaGymaiaaicdacaWG0bWaaWbaaSqabeaacaaIYaaaaOGaey4kaSIaaGioaaqaaiaadshacqGH9aqpcaaI0aGaamyqeaqaaiaac+facaGGFbGaai4xaiaac+facaGGFbGaai4xaiaac+facaGGFbGaai4xaiaac+facaGGFbGaai4xaiaac+facaGGFbGaai4xaiaac+faaeaacaWGwbGaeyOeI0Iaai4paaqaaiaadggacqGHsislcaGG=aaaaiaawIa7aaaa@5C88@

Решение. Зависимость скорости тела от времени найдем по формуле

V= dS dt MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaacaWGKbGaam4uaaqaaiaadsgacaWG0baaaaaa@39A8@ V= d dt (2 t 3 10 t 2 +8)=6 t 2 20t MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaacaWGKbaabaGaamizaiaadshaaaGaaiikaiaaikdacaWG0bWaaWbaaSqabeaacaaIZaaaaOGaeyOeI0IaaGymaiaaicdacaWG0bWaaWbaaSqabeaacaaIYaaaaOGaey4kaSIaaGioaiaacMcacqGH9aqpcaaI2aGaamiDamaaCaaaleqabaGaaGOmaaaakiabgkHiTiaaikdacaaIWaGaamiDaaaa@49D2@ (1)

Скорость тела в момент времени t=4 c

V=6*42-20*4=16 м/c

Ускорение тела найдем по формуле

a= dV dt MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaacaWGKbGaamOvaaqaaiaadsgacaWG0baaaaaa@39AB@ a= d dt (6 t 2 20t)=12t20 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaacaWGKbaabaGaamizaiaadshaaaGaaiikaiaaiAdacaWG0bWaaWbaaSqabeaacaaIYaaaaOGaeyOeI0IaaGOmaiaaicdacaWG0bGaaiykaiabg2da9iaaigdacaaIYaGaamiDaiabgkHiTiaaikdacaaIWaaaaa@460A@

Ускорение тела в момент времени t=4 c

a=12*4-20=28 м/ с 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamipeiaac+cacaWGbrWaaWbaaSqabeaacaaIYaaaaaaa@3920@

Ответ: V=16 м/с а=28 м/ с 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamipeiaac+cacaWGbrWaaWbaaSqabeaacaaIYaaaaaaa@3920@


 

Возврат в начало

Пример решения задачи по физике 2. Динамика

Какую силу надо приложить к вагону, стоящему на рельсах, чтобы вагон стал двигаться равноускоренно и за время t=30 с прошел путь S=11 м? Во время движения на вагон действует сила трения F тр =8 10 3 Н MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOramaaBaaaleaacaWGcrGaamiqeaqabaGccqGH9aqpcaaI4aGaeyOiGCRaaGymaiaaicdadaahaaWcbeqaaiaaiodaaaGccaWGDqaaaa@3EE6@ . Масса вагона m= 16 10 3 кг MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGymaiaaiAdacqGHIaYTcaaIXaGaaGimamaaCaaaleqabaGaaG4maaaakiaadQdbcaWGZqaaaa@3CDD@ . Дано: t=30с S=11м F тр =8 10 3 Н m=16 10 3 кг V 0 =0 _______________ F? | MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=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@68B6@

Решение.

Воспользуемся 2 законом Ньютона:

F + F тр +m g + N =m a MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaa8HaaeaacaWGgbaacaGLxdcacqGHRaWkdaWhcaqaaiaadAeadaWgaaWcbaGaamOqeiaadcebaeqaaaGccaGLxdcacqGHRaWkcaWGTbWaa8HaaeaacaWGNbaacaGLxdcacqGHRaWkdaWhcaqaaiaad6eaaiaawEniaiabg2da9iaad2gadaWhcaqaaiaadggaaiaawEniaaaa@4A0E@ (1)

Или в проекции на ось ОХ

ОХ: F F тр =ma MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOraiabgkHiTiaadAeadaWgaaWcbaGaamOqeiaadcebaeqaaOGaeyypa0JaamyBaiaadggaaaa@3D20@ (2)

Путь пройденный телом за время t при равноускоренном движении

S= V 0 t+ a t 2 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvamaaBaaaleaacaaIWaaabeaakiaadshacqGHRaWkdaWcaaqaaiaadggacaWG0bWaaWbaaSqabeaacaaIYaaaaaGcbaGaaGOmaaaaaaa@3D39@ (3)

Так как V 0 =0 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvamaaBaaaleaacaaIWaaabeaakiabg2da9iaaicdaaaa@3980@ , то (3) примет вид

S= a t 2 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaacaWGHbGaamiDamaaCaaaleqabaGaaGOmaaaaaOqaaiaaikdaaaaaaa@3993@ (4)

Из (4) выразим ускорение и подставим в (2)

a= 2S t 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiabg2da9maalaaabaGaaGOmaiaadofaaeaacaWG0bWaaWbaaSqabeaacaaIYaaaaaaaaaa@3B67@ F F тр = 2mS t 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOraiabgkHiTiaadAeadaWgaaWcbaGaamOqeiaadcebaeqaaOGaeyypa0ZaaSaaaeaacaaIYaGaamyBaiaadofaaeaacaWG0bWaaWbaaSqabeaacaaIYaaaaaaaaaa@3FC0@ (5)

Из (5) найдем силу

F= 2mS t 2 + F тр MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOraiabg2da9maalaaabaGaaGOmaiaad2gacaWGtbaabaGaamiDamaaCaaaleqabaGaaGOmaaaaaaGccqGHRaWkcaWGgbWaaSbaaSqaaiaadkebcaWGaraabeaaaaa@3FB5@

Проверим размерность

[ F ]= 2[ m ][ S ] [ t ] 2 +[ F тр ]= кгм с 2 +Н=Н MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaamWaaeaacaWGgbaacaGLBbGaayzxaaGaeyypa0ZaaSaaaeaacaaIYaWaamWaaeaacaWGTbaacaGLBbGaayzxaaWaamWaaeaacaWGtbaacaGLBbGaayzxaaaabaWaamWaaeaacaWG0baacaGLBbGaayzxaaWaaWbaaSqabeaacaaIYaaaaaaakiabgUcaRmaadmaabaGaamOramaaBaaaleaacaWGcrGaamiqeaqabaaakiaawUfacaGLDbaacqGH9aqpdaWcaaqaaiaadQdbcaWGZqGaeyyXICTaamipeaqaaiaadgebdaahaaWcbeqaaiaaikdaaaaaaOGaey4kaSIaamyheiabg2da9iaad2bbaaa@540E@

F= 216 10 3 11 4 2 +8 10 3 =3 10 4 Н MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOraiabg2da9maalaaabaGaaGOmaiabgwSixlaaigdacaaI2aGaeyyXICTaaGymaiaaicdadaahaaWcbeqaaiaaiodaaaGccqGHflY1caaIXaGaaGymaaqaaiaaisdadaahaaWcbeqaaiaaikdaaaaaaOGaey4kaSIaaGioaiabgwSixlaaigdacaaIWaWaaWbaaSqabeaacaaIZaaaaOGaeyypa0JaaG4maiabgwSixlaaigdacaaIWaWaaWbaaSqabeaacaaI0aaaaOGaamyheaaa@53EF@

Ответ: F=3 10 4 Н MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOraiabg2da9iaaiodacqGHflY1caaIXaGaaGimamaaCaaaleqabaGaaGinaaaakiaad2bbaaa@3DDD@


Возврат в начало

Пример решения задачи по физике 3.  Электричество и магнетизм

Участок электрической цепи составлен из трех кусков провода одинаковой длинны, изготовленных из одного и того же материала, соединенных последовательно. Сечения кусков провода равны S 1 =1м м 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uamaaBaaaleaacaaIXaaabeaakiabg2da9iaaigdacaWG8qGaamipemaaCaaaleqabaGaaGOmaaaaaaa@3BF2@ , S 2 =2м м 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uamaaBaaaleaacaaIYaaabeaakiabg2da9iaaikdacaWG8qGaamipemaaCaaaleqabaGaaGOmaaaaaaa@3BF4@ , S 3 =3м м 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uamaaBaaaleaacaaIZaaabeaakiabg2da9iaaiodacaWG8qGaamipemaaCaaaleqabaGaaGOmaaaaaaa@3BF6@ . Разность потенциалов на концах участка U=12 В. Найти разность потенциалов на каждом куске провода.

Дано: l 1 = l 2 = l 3 =l ρ 1 = ρ 2 = ρ 3 =ρ S 1 = 10 6 м 2 S 2 =2 10 6 м 2 S 1 =3 10 6 м 2 U=12В ______________ U 1 ? U 2 ? U 3 ? | MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=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aaaaiaawIa7aaaa@8A4E@

Решение.

Наше соединение проводов можно схематически изобразить При последовательном соединении проводников, общее сопротивление

Сила тока в цепи, согласно закону Ома R= R 1 + R 2 + R 3 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOuaiabg2da9iaadkfadaWgaaWcbaGaaGymaaqabaGccqGHRaWkcaWGsbWaaSbaaSqaaiaaikdaaeqaaOGaey4kaSIaamOuamaaBaaaleaacaaIZaaabeaaaaa@3EE7@ (1)

I= U R MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamysaiabg2da9maalaaabaGaamyvaaqaaiaadkfaaaaaaa@398A@ (2)

Подставим (1) в (2)

I= U R 1 + R 2 + R 3 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamysaiabg2da9maalaaabaGaamyvaaqaaiaadkfadaWgaaWcbaGaaGymaaqabaGccqGHRaWkcaWGsbWaaSbaaSqaaiaaikdaaeqaaOGaey4kaSIaamOuamaaBaaaleaacaaIZaaabeaaaaaaaa@3FC8@ (3)

При последовательном соединении проводников сила тока на каждом участке одинаковая и равна силе тока в цепи. Следовательно, напряжение на первом участке U 1 =I R 1 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyvamaaBaaaleaacaaIXaaabeaakiabg2da9iaadMeacaWGsbWaaSbaaSqaaiaaigdaaeqaaaaa@3B52@ (4)

Подставим (3) в (4)

U 1 = U R 1 R 1 + R 2 + R 3 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyvamaaBaaaleaacaaIXaaabeaakiabg2da9maalaaabaGaamyvaiaadkfadaWgaaWcbaGaaGymaaqabaaakeaacaWGsbWaaSbaaSqaaiaaigdaaeqaaOGaey4kaSIaamOuamaaBaaaleaacaaIYaaabeaakiabgUcaRiaadkfadaWgaaWcbaGaaG4maaqabaaaaaaa@428D@ (5)

Сопротивление каждого участка

R 1 =ρ l 1 S 1 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOuamaaBaaaleaacaaIXaaabeaakiabg2da9iabeg8aYnaalaaabaGaamiBamaaBaaaleaacaaIXaaabeaaaOqaaiaadofadaWgaaWcbaGaaGymaaqabaaaaaaa@3E34@ (6)

R 2 =ρ l 2 S 2 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOuamaaBaaaleaacaaIYaaabeaakiabg2da9iabeg8aYnaalaaabaGaamiBamaaBaaaleaacaaIYaaabeaaaOqaaiaadofadaWgaaWcbaGaaGOmaaqabaaaaaaa@3E37@ (7)

R 3 =ρ l 3 S 3 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOuamaaBaaaleaacaaIZaaabeaakiabg2da9iabeg8aYnaalaaabaGaamiBamaaBaaaleaacaaIZaaabeaaaOqaaiaadofadaWgaaWcbaGaaG4maaqabaaaaaaa@3E3A@ (8)

Подставим (6), (7) и (8) в (5), получим

U 1 = U S 1 1 S 1 + 1 S 2 + 1 S 3 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyvamaaBaaaleaacaaIXaaabeaakiabg2da9maalaaabaWaaSaaaeaacaWGvbaabaGaam4uamaaBaaaleaacaaIXaaabeaaaaaakeaadaWcaaqaaiaaigdaaeaacaWGtbWaaSbaaSqaaiaaigdaaeqaaaaakiabgUcaRmaalaaabaGaaGymaaqaaiaadofadaWgaaWcbaGaaGOmaaqabaaaaOGaey4kaSYaaSaaaeaacaaIXaaabaGaam4uamaaBaaaleaacaaIZaaabeaaaaaaaaaa@4502@

[ U 1 ]= [ U ] [ S 1 ] 1 [ S 1 ] + 1 [ S 2 ] + 1 [ S 3 ] = В м 2 1 м 2 + 1 м 2 + 1 м 2 =В MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=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@5F1F@

Аналогично можно получить напряжение для второго и третьего участков

U 2 = U S 2 1 S 1 + 1 S 2 + 1 S 3 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyvamaaBaaaleaacaaIYaaabeaakiabg2da9maalaaabaWaaSaaaeaacaWGvbaabaGaam4uamaaBaaaleaacaaIYaaabeaaaaaakeaadaWcaaqaaiaaigdaaeaacaWGtbWaaSbaaSqaaiaaigdaaeqaaaaakiabgUcaRmaalaaabaGaaGymaaqaaiaadofadaWgaaWcbaGaaGOmaaqabaaaaOGaey4kaSYaaSaaaeaacaaIXaaabaGaam4uamaaBaaaleaacaaIZaaabeaaaaaaaaaa@4504@

U 3 = U S 3 1 S 1 + 1 S 2 + 1 S 3 MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyvamaaBaaaleaacaaIZaaabeaakiabg2da9maalaaabaWaaSaaaeaacaWGvbaabaGaam4uamaaBaaaleaacaaIZaaabeaaaaaakeaadaWcaaqaaiaaigdaaeaacaWGtbWaaSbaaSqaaiaaigdaaeqaaaaakiabgUcaRmaalaaabaGaaGymaaqaaiaadofadaWgaaWcbaGaaGOmaaqabaaaaOGaey4kaSYaaSaaaeaacaaIXaaabaGaam4uamaaBaaaleaacaaIZaaabeaaaaaaaaaa@4506@

U 1 = 12 10 6 1 10 6 + 1 2 10 6 + 1 3 10 6 =6,54В MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyvamaaBaaaleaacaaIXaaabeaakiabg2da9maalaaabaWaaSaaaeaacaaIXaGaaGOmaaqaaiaaigdacaaIWaWaaWbaaSqabeaacqGHsislcaaI2aaaaaaaaOqaamaalaaabaGaaGymaaqaaiaaigdacaaIWaWaaWbaaSqabeaacqGHsislcaaI2aaaaaaakiabgUcaRmaalaaabaGaaGymaaqaaiaaikdacqGHflY1caaIXaGaaGimamaaCaaaleqabaGaeyOeI0IaaGOnaaaaaaGccqGHRaWkdaWcaaqaaiaaigdaaeaacaaIZaGaeyyXICTaaGymaiaaicdadaahaaWcbeqaaiabgkHiTiaaiAdaaaaaaaaakiabg2da9iaaiAdacaGGSaGaaGynaiaaisdacaWGsqaaaa@5681@

U 2 = 12 2 10 6 1 10 6 + 1 2 10 6 + 1 3 10 6 =3,27В MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyvamaaBaaaleaacaaIYaaabeaakiabg2da9maalaaabaWaaSaaaeaacaaIXaGaaGOmaaqaaiaaikdacqGHflY1caaIXaGaaGimamaaCaaaleqabaGaeyOeI0IaaGOnaaaaaaaakeaadaWcaaqaaiaaigdaaeaacaaIXaGaaGimamaaCaaaleqabaGaeyOeI0IaaGOnaaaaaaGccqGHRaWkdaWcaaqaaiaaigdaaeaacaaIYaGaeyyXICTaaGymaiaaicdadaahaaWcbeqaaiabgkHiTiaaiAdaaaaaaOGaey4kaSYaaSaaaeaacaaIXaaabaGaaG4maiabgwSixlaaigdacaaIWaWaaWbaaSqabeaacqGHsislcaaI2aaaaaaaaaGccqGH9aqpcaaIZaGaaiilaiaaikdacaaI3aGaamOeeaaa@5985@

U 3 = 12 3 10 6 1 10 6 + 1 2 10 6 + 1 3 10 6 =2,18В MathType@MTEF@5@5@+=feaagCart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyvamaaBaaaleaacaaIZaaabeaakiabg2da9maalaaabaWaaSaaaeaacaaIXaGaaGOmaaqaaiaaiodacqGHflY1caaIXaGaaGimamaaCaaaleqabaGaeyOeI0IaaGOnaaaaaaaakeaadaWcaaqaaiaaigdaaeaacaaIXaGaaGimamaaCaaaleqabaGaeyOeI0IaaGOnaaaaaaGccqGHRaWkdaWcaaqaaiaaigdaaeaacaaIYaGaeyyXICTaaGymaiaaicdadaahaaWcbeqaaiabgkHiTiaaiAdaaaaaaOGaey4kaSYaaSaaaeaacaaIXaaabaGaaG4maiabgwSixlaaigdacaaIWaWaaWbaaSqabeaacqGHsislcaaI2aaaaaaaaaGccqGH9aqpcaaIYaGaaiilaiaaigdacaaI4aGaamOeeaaa@5986@

Ответ: U1=6,54 В, U2=3,27 В, U3=2,18 В


Возврат в начало

TopEnter


Домашняя | Англ. яз. | Высшая математика | Физика | Теория вероятностей | Статистика | Мат. программирование | Дискретная математика | Программирование | Электротехника | ТерМех | Биология | Химия | Экономика | Курсовые | Все предметы | УО | Вакансии

ИП Пантелей О.А. Св. № 190852728 Мингорисполкома, 2007-2017.  Все права защищены.
Последнее изменение: 22.08.2017.
 

Jovo- -  

Каталог Ресурсов Интернет